00:01
In this problem, we are going to calculate the smallest angle of the incidence for which light can emerge from the other side of the prism.
00:08
So we need to calculate this theta 1.
00:14
Now let's draw the diagram first.
00:24
So here we have prism where we incident a light at this point which makes an angle of incidence theta 1.
00:32
Then it goes into this direction and it makes an angle of theta 3 with the normal at this point and here we have an angle theta 2 and we have the apex angle as 60 degree.
00:44
Now let's apply the snail slide to the side 1.
00:49
So from side 1 we can write 1 .00 sine theta 1 is equal to and sine theta.
01:05
Let's call it equation number 1.
01:09
Now by applying the same loit the side 2 we can write n sine theta 3 is equals to 1 .00 sign of 90 degree so from here we can write the equation for this theta 3 as theta 3 is equal to sine inverse of 1 .00 divided by 1 .50 where this 1 .50 is the index of refraction of this prism.
01:51
So from here we can write the value for this theta 3 as theta 3 is equals to 41 .8 degree...