A truck on a straight road starts from rest, accelerating at 2.00 m / s^2 until it reaches a spe

step 1 Hi everyone in this problem it is given a truck on a straight road starts from rest so initial v

A truck on a straight road starts from rest, accelerating at...

A truck on a straight road starts from rest, accelerating at $2.00 \mathrm{m} / \mathrm{s}^{2}$ until it reaches a speed of $20.0 \mathrm{m} / \mathrm{s} .$ Then the truck travels for $20.0 \mathrm{s}$ at constant speed until the brakes are applied, stopping the truck in a uniform manner in an additional $5.00 \mathrm{s}$. (a) How long is the truck in motion? (b) What is the average velocity of the truck for the motion described?

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Key Concepts

Uniform Acceleration

Uniform acceleration describes a change in velocity that occurs at a constant rate, allowing the use of kinematic equations such as v = u + at and s = ut + 0.5at². In situations like the truck accelerating from rest, this concept helps determine both the final speed reached and the distance covered during the acceleration phase.

Constant Velocity Motion

Constant velocity motion occurs when an object moves at a steady speed, meaning its acceleration is zero. In this phase, the displacement is calculated simply by multiplying the constant speed by the time spent moving at that speed, as there is no change in velocity.

Uniform Deceleration

Uniform deceleration is a specific case of uniform acceleration where the acceleration is negative, causing the object’s speed to decrease at a constant rate. This concept is used to determine the stopping time and the distance over which an object like the truck comes to a halt uniformly.

Average Velocity Calculation

Average velocity is defined as the total displacement divided by the total time taken for the journey. When an object undergoes different phases of motion—such as acceleration, constant velocity, and deceleration—the overall displacement is the sum of the displacements in each phase, and the total time is the sum of all the individual time intervals.

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