Question
A tuning fork of frequency $200 \mathrm{~Hz}$ is in unison with a sonometer wire. The number of beats heard per second when the tension is increased by $1 \%$ is $\ldots \ldots \ldots .$(A) 1(B) 2(C) 4(D) $0.5$
Step 1
Step 1: We know that the frequency of a sonometer wire is given by the formula $f = \sqrt{\frac{T}{\mu}}$, where $T$ is the tension in the wire and $\mu$ is the linear mass density of the wire. Show more…
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A tuning fork of frequency $200 \mathrm{~Hz}$ is in unison with a sonometer wire. The number of beats heard per second when the tension is increased by $1 \%$ is (a) 1 (2) 2 (c) 4 (d) $1 / 2$
Waves
Round 1
A stretched sonometer wire is in unison with a tuning fork. When the length of the wire is increased by $2 \%$, the number of beats heard per second is 5 . Then the frequency of the fork is (A) $245 \mathrm{~Hz}$ (B) $250 \mathrm{~Hz}$ (C) $255 \mathrm{~Hz}$ (D) $260 \mathrm{~Hz}$
A tuning fork of frequency $250 \mathrm{~Hz}$ produces a beat frequency of $10 \mathrm{~Hz}$ when sounded with a sonometer vibrating as its fundamental frequency. When the tuning fork is filed, the beat frequency decreases. If the length of sonometer wire is $0.5 \mathrm{~m}$, the speed of transverse wave is (a) $260 \mathrm{~ms}^{-1}$ (b) $250 \mathrm{~ms}^{-1}$ (c) $240 \mathrm{~ms}^{-1}$ (d) $500 \mathrm{~ms}^{-1}$
Round 2
Transcript
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