Question
A uniform block of steel $(\mathrm{SG}=7.85)$ will "float" at a mercury-water interface as in Fig. P2.122. What is the ratio of the distances $a$ and $b$ for this condition?
Step 1
The forces acting on the block are the buoyant forces from the mercury and the water, and the weight of the block. The buoyant force from the mercury is equal to the weight of the mercury displaced by the block, which is the volume of the block submerged in the Show more…
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Mercury is poured into a U-tube as shown in Figure $\mathrm{Pl} 5.17$ a . The left arm of the tube has cross-sectional area $A_{1}$ of $10.0 \mathrm{cm}^{2},$ and the right arm has a cross-sectional area $A_{2}$ of $5.00 \mathrm{cm}^{2} .$ One hundred grams of water are then poured into the right arm as shown in Figure $P 15.17$ b. (a) Determine the length of the water column in the right arm of the U-tube. (b) Given that the density of mercury is $13.6 \mathrm{g} / \mathrm{cm}^{3},$ what distance $h$ does the mercury rise in the left arm?
A cubical block of density $\rho_{\mathrm{B}}$ and with sides of length $L$ floats in a liquid of greater density $\rho_{\mathrm{L}}$. (a) What fraction of the block's volume is above the surface of the liquid? (b) The liquid is denser than water (density $\rho_{\mathrm{W}}$ ) and does not mix with it. If water is poured on the surface of that liquid, how deep must the water layer be so that the water surface just rises to the top of the block? Express your answer in terms of $L, \rho_{\mathrm{B}}, \rho_{\mathrm{L}},$ and $\rho_{\mathrm{W}} .$ (c) Find the depth of the water layer in part (b) if the liquid is mercury, the block is made of iron, and $L=11.5 \mathrm{~cm}$.
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