A uniform conducting wire ABC has a mass 10 gram. A 12 Amp current is flowing through it. The wi

Name: Problem 1940, Chapter 13: JEE Physics
Uploaded: 2021-10-02T09:23:14-08:00
Duration: 1 min 5 s
Channel: Narayan Hari
Description: A uniform conducting wire ABC has a mass 10 gram. A 12 Amp current is flowing through it. The wire is kept in uniform magnetic field B⃗=2 tesla the acceleration of the wire will be(a) zero (b) 12 m / s^2 along y -axis (c) 1.2 ×10^-3( m / s^2) along y -axis (d) 0.6 ×10^-3( m / s^2) along y -axis

step 1 magnetic force on straight wire f is equal to b i l f is equal to b i l sine theta is equal to 9

A uniform conducting wire ABC has a mass 10 gram. A 12 Amp...

A uniform conducting wire $\mathrm{ABC}$ has a mass 10 gram. $\mathrm{A}$ 12 Amp current is flowing through it. The wire is kept in uniform magnetic field $\vec{B}=2$ tesla the acceleration of the wire will be(a) zero (b) $12 \mathrm{~m} / \mathrm{s}^{2}$ along $\mathrm{y}$ -axis (c) $1.2 \times 10^{-3}\left(\mathrm{~m} / \mathrm{s}^{2}\right)$ along $\mathrm{y}$ -axis (d) $0.6 \times 10^{-3}\left(\mathrm{~m} / \mathrm{s}^{2}\right)$ along $\mathrm{y}$ -axis

A uniform conducting wire $\mathrm{ABC}$ has a mass 10 gram. $\mathrm{A}$ 12 Amp current is flowing through it. The wire is kept in uniform magnetic field $\vec{B}=2$ tesla the acceleration of the wire will be(a) zero
(b) $12 \mathrm{~m} / \mathrm{s}^{2}$ along $\mathrm{y}$ -axis
(c) $1.2 \times 10^{-3}\left(\mathrm{~m} / \mathrm{s}^{2}\right)$ along $\mathrm{y}$ -axis
(d) $0.6 \times 10^{-3}\left(\mathrm{~m} / \mathrm{s}^{2}\right)$ along $\mathrm{y}$ -axis

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Key Concepts

Lorentz Force

This is the fundamental force experienced by moving charges in the presence of a magnetic field. In the context of conductors, the microscopic charge carriers (typically electrons) moving through a magnetic field experience forces that sum to produce the net force on the whole conductor.

Force on a Current-Carrying Conductor

When an electric current flows through a conductor placed in a magnetic field, every segment of the wire is subjected to a force given by F = I (L × B). The magnitude and direction of this force depend on the current I, the length and orientation of the conductor L, and the magnetic field B, following the right-hand rule.

Uniform Magnetic Field Effects on a Closed Circuit

In a uniform magnetic field, while individual segments of a closed current loop may experience forces, these forces can cancel out if the geometry of the circuit is symmetric. As a result, the net force acting on the entire setup can be zero, despite the presence of local magnetic forces.

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