Question
A uniform cube with mass $0.500 \mathrm{~kg}$ and volume $0.0270 \mathrm{~m}^{3}$ is sitting on the floor. A uniform sphere with radius $0.400 \mathrm{~m}$ and mass $0.800 \mathrm{~kg}$ sits on top of the cube. How far is the center of mass of the two-object system above the floor?
Step 1
Since the volume of a cube is given by $s^3$ where $s$ is the side length, we can find $s$ by taking the cube root of the volume. So, $s = \sqrt[3]{0.0270 \mathrm{~m}^{3}} = 0.3 \mathrm{~m}$. Show more…
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A uniform cube with mass $0.500 \mathrm{~kg}$ and volume $0.0270 \mathrm{~m}^{3}$ is sitting on the floor. A uniform sphere with radius $0.400 \mathrm{~m}$ and mass $0.800 \mathrm{~kg}$ sits on top of the cubc. How far is the center of mass of the two-object system above the floor?
A uniform cube with mass 0.500 kg and volume 0.0270 m3 is sitting on the floor. A uniform sphere with radius 0.400 m and mass 0.800 kg sits on top of the cube. How far is the center of mass of the two-object system above the floor?
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