Question
A uniform cube with mass $0.500 \mathrm{~kg}$ and volume $0.0270 \mathrm{~m}^{3}$ is sitting on the floor. A uniform sphere with radius $0.400 \mathrm{~m}$ and mass $0.800 \mathrm{~kg}$ sits on top of the cubc. How far is the center of mass of the two-object system above the floor?
Step 1
We know that the volume of a cube is given by the formula $V = a^3$, where $a$ is the length of a side. Given that the volume of the cube is $0.0270 \, m^3$, we can solve for $a$: \[a = \sqrt[3]{V} = \sqrt[3]{0.0270 \, m^3} = 0.3 \, m\] Show more…
Show all steps
Your feedback will help us improve your experience
Sachin Rao and 80 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A uniform cube with mass $0.500 \mathrm{~kg}$ and volume $0.0270 \mathrm{~m}^{3}$ is sitting on the floor. A uniform sphere with radius $0.400 \mathrm{~m}$ and mass $0.800 \mathrm{~kg}$ sits on top of the cube. How far is the center of mass of the two-object system above the floor?
A uniform cube with mass 0.500 kg and volume 0.0270 m3 is sitting on the floor. A uniform sphere with radius 0.400 m and mass 0.800 kg sits on top of the cube. How far is the center of mass of the two-object system above the floor?
A uniform cube with mass 0.300 kg and volume 0.0270 m3 is sitting on the floor. A uniform sphere with radius 0.300 m and mass 0.900 kg sits on top of the cube.
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD