00:01
We have three functions in complex space.
00:09
Function 1 is 1.
00:14
Function 2 is the sign of pi x, and function 3 is the cosine of pi x.
00:33
We need to show that they are orthogonal first.
00:38
So the inner product of f1, f2, would be the integral over the interval from negative 1 to 1 of f of x, f1 of x, which is just going to be the sign of pi x.
01:09
So we take the integral and we get the sign of pi x.
01:26
That should be cosine, opposite of cosine of pi x over pi, from negative 1 to 1.
01:40
So the cosine of pi is negative 1, and the cosine of the opposite of the opposite of pi is also negative 1.
01:53
So we get negative 1 over pi minus negative 1 over pi, which is 0.
02:10
F1, the inner product of f1 and f3, integral from negative 1 to 1 of the cosine of pi x, which would be the sign of pi x over pi x over pi, from negative 1 to 1.
02:33
The sign of pi is 0.
02:36
The sign of negative pi is 0.
02:38
That's going to give us 0 minus 0, which is 0.
02:47
F2, f3, the inner product.
02:49
That's going to be the integral from negative 1 to 1 of sine of pi x, cosine of pi.
03:06
X dx should have been writing dx on all these which is the same as the integral from negative one to one using double angle identities um two sine x cosine x equals a sign of two x so we could just write in sine of 2 pi x over 2 d x, which is going to be negative cosine of 2x over 2 pi x, which would be negative cosine of 2 pi x over 2 times 2 pi, which would be 4 pi, from negative 1 to 1 to 1.
04:28
So that's going to be the cosine of 2 pi, which is the same as the cosine of 0, and the cosine of 0 is 1.
04:38
And then the second one is going to be the cosine of negative 2 pi, which is going to be the same thing, 1.
04:43
So it's going to give us negative 1 over 4 pi minus negative 1 over 4 pi, which is 0.
04:57
Now we need to make an orthonormal set.
05:02
And so first thing we need to do is we need to do the norm of f1, which is going to be the square root of the integral from negative 1 to 1 of f1 of f1 is just 1.
05:28
F1 squared is just going to be 1 squared.
05:32
Dx.
05:34
Okay, so that's going to give us the integral of 1 is x from negative 1 to 1.
05:52
Okay.
05:53
Oh, good.
05:54
And that's going to give us the square root of 1 minus negative 1.
05:59
I thought we were going to end up with 0, which would be not good.
06:04
So that's the square root of 2...