00:01
So in this problem, we're asked to use numerical and graphical methods to show what the limit is x goes to 1 of this function, x cubed minus 1 over the square root of x minus 1 equals.
00:30
So first of all, numerically, let's make a table here of x's and f of x.
00:41
Okay.
00:43
We'll have our xs go to 1, first from the left.
00:46
So if you put 0 .5 into this formula, you get 2 .987, 0 .75 in here.
00:56
You get 4 .315.
01:00
0 .90 in here.
01:02
You get 5 .281, inching our way towards 1, right? 0 .93 gives me 5 .49 .0 .99.
01:21
Gives me 5 .925.
01:26
0 .999.
01:30
Gives me 5 .9925.
01:33
All right, so this suggests that the limit, as x approaches one from the left of our function is six doesn't it all right now let's go from the other way let's start at 1 .1 that's 6 .782 and 1 .065 is 6 .501 1 .01 is 6 .0701 is 6 .075 1 .01 is 6 .075 .1 is 6 .075 1 .001.
02:21
See, i'm getting closer to 1.
02:23
6 .0075.
02:27
So this suggests that the limit as x approaches 1 from the right then, right? i'm coming in closer from the right of our function is also 6.
02:40
So, since i have the same limit from the left and the right, then i have the limit.
02:48
It's not writing very neatly.
02:50
Let me try that again.
02:52
Limit as x approaches 1 of x cubed minus 1 over the square root of x minus 1.
03:02
This function is 6, numerically, isn't it? all right, let's see it graphically now.
03:11
I look at it graphically...