00:01
This question is about resolving radio waves.
00:05
And we're told that the diameter is 26 meters, and the frequency, radio frequency, is 6 .6 gigahertz.
00:25
Speed of light is wavelength times frequency.
00:30
So wavelength is going to be speed of light over frequency, where the speed of light is 3 times 10 to the 8th power meters per second.
00:50
So a, the wavelength corresponding to that frequency is just speed of light divided by frequency, which is 3 times 10 to the 8th power, divided by 6 .6 times 10 to the 3 .6 to the 3.
01:08
9th power.
01:12
0 .046 meters.
01:30
Angular separation of the radio sources.
01:35
So now i'm going to use sine theta equals lambda m over w.
01:47
No, i'm not going to use that.
01:48
My bad.
01:51
Let's erase that.
01:53
Paper, theta equals 1 .22 lambda over d.
02:03
So that's the same as 1 .22, c over f, d.
02:15
So i've got c over f, d is 26, and 1 .22, 1 .22 c over f, d.
02:24
1 .22, c over f, d is 26, and 1 .22.
02:30
1 .22, c over f, d...