00:01
We want to combine two different lenses with different indexes of refraction together, in which the effective focal length of this combination is the same for two different wavelengths.
00:18
How do we do that? well, problem 4 noted that in problem 3, we should use the result, which i have highlighted here in a box, in which one over the effective focal length is equal to one over the focal length of the first lens, plus one over the focal length of the second lens.
00:42
Okay, so let's first note that since the effective focal lengths are equivalent across both wavelengths, we can simply do one divided by each.
00:57
And now we note that we can just insert the result from problem 3 into both sides of the equal sign.
01:08
Okay, so what do we get? once we substitute in, we get 1 over f1, landa 1 plus 1 over f2.
01:23
Landa 1 is equal to 1 over f1.
01:30
Landa 2 plus 1 over f2 landa.
01:41
Now we have to note the lensmaker equation in which we have, and i'm going to put this in another box, 1 over the focal length for a certain wavelength is equal to 1 minus the index of refraction for that wavelength.
02:02
And then we have one over one side of the curvature of the lens plus one over the second side the curvature of the second side of the lens in which what i mean by curvature is the radius of curvature and we are now going to just to simplify since it's pretty much treated as a constant we're going to treat this region here as equal to s...