A vacuum tube diode (see Exercise 23.27$)$ consists of con- centric cylindrical electrodes, the negative cathode and the positive anode. Because of the accumulation of charge near the cathode, the electric potential between the electrodes is not a linear function of the position, even with planar geometry, but is given by $$ V(x)=C x^{4 / 3} $$ where $x$ is the distance from the cathode and $C$ is a constant, characteristic of a particular diode and operating conditions. Assume that the distance between the cathode and anode is 13.0 $\mathrm{mm}$ and the potential difference between electrodes is 240 $\mathrm{V}$ . (a) Determine the value of $C .$ ( b) Obtain a formula for the electric field between the electrodes as a function of $x$ . (c) Determine the force on an electron when the electron is halfway between the electrodes.