Question
A vertebra is subjected to a shearing force of 500 N. Find the shear deformation, taking the vertebra to be a cylinder $3.00 \mathrm{cm}$ high and $4.00 \mathrm{cm}$ in diameter.
Step 1
Step 1: We start by using the formula for shear deformation, which is given by $\Delta s = \frac{F}{S \cdot A}$, where $\Delta s$ is the shear deformation, $F$ is the shearing force, $S$ is the shear modulus, and $A$ is the area. Show more…
Show all steps
Your feedback will help us improve your experience
Mayukh Banik and 50 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A vertebra is subjected to a shearing force of 530 N. Find the shear deformation, taking the vertebra to be a cylinder 3.00 cm high and 3.00 cm in diameter. The shear modulus for vertebrae is 8.0×10^10 N/m^2. shear deformation: _______ m
A disk between vertebrae in the spine is subjected to a shearing force of 600 $\mathrm{N}$ . Find its shear deformation, taking it to have the shear modulus of $1 \times 10^{9} \mathrm{N} / \mathrm{m}^{2}$ . The disk is equivalent to a solid cylinder 0.700 $\mathrm{cm}$ high and 4.00 $\mathrm{cm}$ in diameter.
During heavy lifting, a disk between spinal vertebrae is subjected to a $5000-\mathrm{N}$ compressional force. (a) What pressure is created, assuming that the disk has a uniform circular cross section 2.00 $\mathrm{cm}$ in radius? (b) What deformation is produced if the disk is 0.800 $\mathrm{cm}$ thick and has a Young's modulus of $1.5 \times 10^{9} \mathrm{N} / \mathrm{m}^{2}$ ?
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD