A vinegar solution is 5.11 % acetic acid. Its density is 1.007 g / mL. What is its molarity?

Name: Problem 16, Chapter 11: Chemistry
Uploaded: 2021-07-29T07:41:00-08:00
Duration: 6 min 53 s
Channel: Marietjie Lutz
Description: A vinegar solution is 5.11 % acetic acid. Its density is 1.007 g / mL. What is its molarity?

A vinegar solution is 5.11 % acetic acid. Its density is...

Key Concepts

Weight Percent

Weight percent, or mass percent, indicates the concentration of a component in a solution by describing the ratio of the mass of the solute to the total mass of the solution, multiplied by 100. This concept is essential when determining the amount of solute present in a given mass of the solution and serves as the starting point for further concentration calculations.

Density

Density is defined as the mass per unit volume of a substance and is often expressed in units such as grams per milliliter. In the context of solution chemistry, it is used to convert between the mass of the solution and its volume, enabling accurate calculations of concentrations from mass-based measurements.

Molarity

Molarity is a measure of the concentration of a solution expressed as the number of moles of solute per liter of solution. This unit is particularly useful in stoichiometry and reaction yield calculations, as it directly relates the amount of active molecules present in a given volume of the solution.

Molar Mass

Molar mass is the mass of one mole of a substance, usually expressed in grams per mole. It is a critical concept in converting between the mass of a substance and the number of moles, thereby allowing for the computation of molarity when the amount of solute is given in grams.

Transcript

00:01 In this question, we need to calculate the malarity of certain percentage solution of vinegar.

00:09 The density of the solution is given as 1 .007 grams per milliliter and the percentage of the solution is 5 .11.

00:19 Now, a 5 .11 percentage vinegar solution actually means that we have 5 .11 grams of solid, 5 .11 grams of solid dissolved in 100 grams of the solution.

00:49 Right.

00:50 So keep that in mind.

00:52 Now, also keep in mind that mularity is determined as moles per liter.

01:03 Right.

01:04 So now, what are we going to do here to solve this question? so we need to realize that for us in order to determine mularity, we need the number of moles of acidic acid.

01:19 Remember vinegar solution that, that's actually acetic acid in solution, which is ch3c -c -o -o -h.

01:31 So we're talking about an acetic acid solution here.

01:37 For us to determine the molarity, i'm just repeating this.

01:41 We need to determine the number of moles of acetic acid, and we also need to determine the volume of the solution.

01:49 Now, in order to determine the number of moles of acetic acids, this is actually easy.

01:57 It's just the mass, which is given us all.

02:04 We've determined in this ratio as 5 .11 grams.

02:11 So it's 5 .11 grams, and we're going to divide it by the molar mass of acetic acid.

02:18 So if we divide by the molar mass, we actually just multiply with the reciprocal.

02:23 And i like to do it that way so that you can see what happens with the units.

02:31 So the molar mass of acid acidity is 60 .1 grams per mole and if i divide with that, i can multiply with the reciprocal and therefore the grams cancel out and i'm left with the number of moles.

02:48 So this is 0 .085 .0 .5.

02:53 Moles...

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