Question
A virtual image is located $40 \mathrm{~cm}$ behind a concave mirror with focal length $18 \mathrm{~cm}$. (a) Where is the object? (b) By how much is the image magnified?
Step 1
We are given f = 18 cm and di = -40 cm (negative because it's a virtual image). Plugging these values into the formula, we get: 1/18 = 1/do - 1/40 To solve for do, we can first find a common denominator for the fractions: (40 - 18) / (18 * 40) = 1/do 22 / 720 Show more…
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