Question
(a) What is the average metabolic rate in watts of a man who metabolizes $10,500 \mathrm{kJ}$ of food energy in one day? (b) What is the maximum amount of work in joules he can do without breaking down fat, assuming a maximum efficiency of $20.0 \% ?(\mathrm{c})$ Compare his work output with the daily output of a 187-W (0.250-horsepower) motor.
Step 1
The energy intake is given as $10,500 \, kJ$ which is equal to $10.5 \times 10^6 \, J$. The time is given as one day which is equal to $24 \times 60 \times 60 = 86,400 \, s$. Show more…
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(a) What is the average metabolic rate in watts of a man who metabolizes 10,500 kJ of food energy in one day? (b) What is the maximum amount of work in joules he can do without breaking down fat, assuming a maximum efficiency of 20.0%? (c) Compare his work output with the daily output of a 187-W (0.250-horsepower) motor.
-Suppose a man metabolizes 12500 kJ of food energy in one day. 1. What is the average metabolic rate, in watts, for this man? 2. What is the maximum amount of work, in joules, he can do without breaking down fat, assuming a maximum efficiency of 22.5 %? 3. How much more work can a 187-W (0.250-horsepower) motor do, as compared with this person over the same time interval?
Suppose a man metabolizes 12000 kJ of food energy in one day. How much more work can a 187-W (0.250-horsepower) motor do, as compared with this person over the same time interval?
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