Question
(a) What is the resistance of the heater element in a $1500-\mathrm{W}$ hair dryer that plugs into a $120-\mathrm{V}$ outlet?(b) What is the current through the hair dryer when it is turned on? (c) At a cost of $\$ 0.10$ per kW .h, how much does it cost to run the hair dryer for 5.00 min? (d) If you were to take the hair dryer to Europe where the voltage is $240 \mathrm{V},$ how much power would your hair dryer be using in the brief time before it is ruined? (e) What current would be flowing through the hair dryer during this time?
Step 1
Rearranging the formula to solve for $R$, we get $R = \frac{V^2}{P}$. Substituting the given values, we get $R = \frac{(120 \, \text{V})^2}{1500 \, \text{W}} = 9.6 \, \Omega$. Show more…
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(a) What is the resistance of the heater element in a $1500 \mathrm{W}$ hair dryer that plugs into a $120 \mathrm{V}$ outlet? (b) What is the current through the hair dryer when it is turned on? (c) At a cost of $\$ 0.10$ per $\mathrm{kW} \cdot \mathrm{h},$ how much does it cost to run the hair dryer for 5.00 min? (d) If you were to take the hair dryer to Europe where the voltage is $240 \mathrm{V}$, how much power would your hair dryer be using in the brief time before it is ruined? (e) What current would be flowing through the hair dryer during this time?
a. What is the resistance of a $1500 \mathrm{W}$ ( $120 \mathrm{V}$ ) hair dryer? b. What is the current in the hair dryer when it is used?
The heating element of an electric dryer is rated at 4.1 kW when connected to a 240-V line. (a) What is the current in the heating element? Is 12-gauge wire large enough to supply this current? (b) What is the resistance of the dryer's heating element at its operating temperature? (c) At 11 cents per kWh, how much does it cost per hour to operate the dryer?
Direct-Current Circuits
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