(a) What must the charge (sign and magnitude) of a 1.45-g particle be for it to remain stationar

step 1 For problem 29, we have an electric field of 650 Newton per colon pointing downwards, an object

(a) What must the charge (sign and magnitude) of a 1.45-g...

(a) What must the charge (sign and magnitude) of a $1.45-\mathrm{g}$ particle be for it to remain stationary when placed in a downward- directed electric field of magnitude 650 $\mathrm{N} / \mathrm{C} 2$ (b) What is the magnitude of an electric field in which the electric force on a proton is equal in magnitnde to its weight?

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Key Concepts

Electric Field

The electric field is a vector field that represents the force per unit charge at each point in space. Its magnitude and direction determine how charges will interact in that region, and it is a fundamental concept in understanding the behavior of charged particles under the influence of electromagnetic forces.

Equilibrium Condition

In the context of forces, equilibrium occurs when the total forces acting on an object sum to zero, resulting in no net motion. For a charged particle in an electric field, this means that the upward electric force must exactly balance the downward gravitational force, leading to the equation qE = mg.

Electric Force

This concept involves the force that a charged particle experiences in an electric field, defined by the equation F = qE. It shows that the force is proportional to both the magnitude of the electric charge and the strength of the electric field, and it acts in the direction of the field for positive charges or opposite for negative charges.

Gravitational Force

This key concept refers to the weight of an object, which is the force due to gravity acting on its mass. It is calculated using the formula F = mg, where m is the mass of the object and g is the acceleration due to gravity, providing a measure of the downward pull experienced by the object.

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