a. What stereoisomers are formed in the following reaction? Are they enantiomers or diastereomers?
b. Which stereoisomer is formed in greater yield?
SOLUTION 40 a. The reaction forms two stereoisomers because $\mathrm{H}_{2}$ can approach the plane of the double bond from above and below. The stereoisomers are diastereomers because the reactant has an asymmetric center and the product has a new second asymmetric center.
SOLUTION 40 b. Because the methyl group is pointing upward, it provides steric hindrance to $\mathrm{H}_{2}$ approaching the double bond from above. Therefore, the major product is $A$, the compound formed by $\mathrm{H}_{2}$ approaching the double bond from below.