Question
A wire is of mass $(0.3 \pm 0.003) \mathrm{gm}$. The radius is $(0.5 \pm 0.005) \mathrm{mm}$ and length is $(6.0 \pm 0.06) \mathrm{cm}$ then$\%$ error in density is(A) 3(B) 4(C) 6(D) $-2$
Step 1
Step 1: The density of the wire can be calculated using the formula: \[ \rho = \frac{m}{V} \] where \( m \) is the mass of the wire, and \( V \) is the volume of the wire. Show more…
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A wire is of mass (0.3 ± 0.003) gm. The radius is (0.5 ± 0.005)mm and length is (6.0 ± 0.06) cm then % error in density is
A wire has a mass $(0.3 \pm 0.003) \mathrm{g}$, radius $(0.5+0.005) \mathrm{mm}$ and length $(6 \pm 0.06) \mathrm{cm}$. The maximum percentage error in the measurement of its density is $\quad$ IITT JEE 2004] (a) 1 (b) 2 (c) 3 (d) 4
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Round 2
A uniform wire of length $\ell=5 \pm 0.05 \mathrm{~cm}$ and radius $\mathrm{r}=0.5 \pm 0.005 \mathrm{~cm}$ has mass $\mathrm{m}=0.4+0.004 \mathrm{~g}$. The maximum percentage error in its density is (a) 1 (b) 2 (c) 4 (d) $5.8$
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