Question
A wire lying along an $x$ axis from $x=0$ to $x=1.00 \mathrm{~m}$ carries a current of $3.00 \mathrm{~A}$ in the positive $x$ direction. The wire is immersed in a nonuniform magnetic field that is given by $\vec{B}=$ $\left.\left(4.00 \mathrm{~T} / \mathrm{m}^{2}\right) x^{2} \hat{\mathrm{i}}-\left(0.600 \mathrm{~T} / \mathrm{m}^{2}\right) x^{2}\right] .$ In unit-vector notation, what isthe magnetic force on the wire?
Step 1
The force on a small segment of the wire in a magnetic field is given by the formula $d\vec{F} = I d\vec{l} \times \vec{B}$, where $I$ is the current, $d\vec{l}$ is the differential length vector, and $\vec{B}$ is the magnetic field. Show more…
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A wire lying along an $x$ axis from $x=0$ to $x=1.00 \mathrm{~m}$ carries a current of $3.00 \mathrm{~A}$ in the positive $x$ direction. The wire is immersed in a nonuniform magnetic field that is given by $\vec{B}=$ $\left(4.00 \mathrm{~T} / \mathrm{m}^{2}\right) x^{2 \hat{i}}-\left(0.600 \mathrm{~T} / \mathrm{m}^{2}\right) x^{2} \mathrm{j} .$ In unit-vector notation, what is the magnetic force on the wire?
A wire lying along an $x$ axis from $x=0$ to $x=1.00 \mathrm{m}$ carries a current of 3.00 $\mathrm{A}$ in the positive $x$ direction. The wire is immersed in a nonuniform magnetic field that is given by $\vec{B}=$ $\left(4.00 \mathrm{T} / \mathrm{m}^{2}\right) x^{2} \mathrm{x}^{2} \mathrm{i}-\left(0.600 \mathrm{T} / \mathrm{m}^{2} \mathrm{x}^{2} \mathrm{j}$ . In unit-vector notation, what is \right. the magnetic force on the wire?
A wire lying along a $y$ axis from $y=0$ to $y=0.250 \mathrm{~m}$ carries a current of $2.00 \mathrm{~mA}$ in the negative direction of the axis. The wire fully lies in a nonuniform magnetic field that is given by $\vec{B}=(0.300 \mathrm{~T} / \mathrm{m}) y \hat{\mathrm{i}}+(0.400 \mathrm{~T} / \mathrm{m}) y \mathrm{j} .$ In unit-vector notation, what is the magnetic force on the wire?
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