00:01
Hi, in the given problem, there is a straight conductor kept along the x -axis and having a length of 20 centimeter.
00:18
Its midpoint, the midpoint of this straight conductor is at the origin and these are the two halves of this straight conductor.
00:30
Each half is having a length of 10 centimeter.
00:38
A current carried by this conductor is i is equal to 8 .00 ampere.
00:49
Then we have to find a magnetic field here at y x is at a point p whose distance from the origin is 4 .0 centimeter.
01:05
If we join it then these two angles let it be 5 -1, let it be 5 -2 and here this is 10 this is 4 so we can find this hypotenuse.
01:22
If you consider these points to be a and b the endpoints of the conductor then in right angle triangle the hypotenuse whether it is a p or or bp, it will be given by pythagoras theorem as the square of 10 plus the square of 4 means this is 100 plus 16 means this is 116 square root centimeter which comes out to be 10 .8 centimeters so we can find the values of sine 5 1 and sine 5 2 and both of them will be actually same whether it is sign 5 1 or sign 5 2 and these will be equal to perpendicular upon hypotenous having the same unit both of them so it will come out to be just 10 by 10 .8 now the magnetic field at point p in the first part of the problem using by 10 7th law will be given by new knot by 4 pi into i by r this distance 4 cm into to sine 51 plus sine 5 5 2.
02:35
So plugging in all known values 10 dash 1 minus 7, tesla meter per ampere for mu not upon 4x by into 4 i, this is 8 ampere for r...