Question
A zener diode with $V_{2}=6 \mathrm{~V}$, operated at a current of $I_{2}=1 \mathrm{~mA}$, has a dynanic resistance $\mathrm{d} V_{2} / \mathrm{d} I_{x}=3 \Omega .$ If the current varies by $2 \%$, what is the fractional change in the voltage?
Step 1
Step 1: Given that the dynamic resistance $dV_{2}/dI_{x}=3 \Omega$, the current variation $\Delta I_{x}/I_{x}=2\%$, and the operating current $I_{x}=1 mA$, we can write the dynamic resistance as: \[dV_{2}/dI_{x}=3 \Omega\] Show more…
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