Question
Americium- 241 is an $\alpha$ -particle emitter, and the rate constant for decay is $1.605 \times 10^{-3} \mathrm{y}^{-1}$.(a) Write an equation for the decay of $^{241} \mathrm{Am}$.(b) Determine the half-life of $^{241} \mathrm{Am}$.
Step 1
Americium-241 (\(^{241}\mathrm{Am}\)) undergoes alpha decay. In alpha decay, an alpha particle, which consists of 2 protons and 2 neutrons (equivalent to a helium nucleus, \(^{4}\mathrm{He}\)), is emitted from the nucleus. Show more…
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