Ammonia, NH3, is very soluble in water (51.8 g / L at 293 K and 101,325 Pa) (a) Show how NH3

step 1 Hi, so in this first part, so a hydrogen bond between NH3 and water is represented like this. So

Ammonia, NH3, is very soluble in water (51.8 g / L at 293...

Ammonia, $\mathrm{NH}_{3}$, is very soluble in water $(51.8 \mathrm{~g} / \mathrm{L}$ at $293 \mathrm{~K}$ and $101,325 \mathrm{~Pa})$
(a) Show how $\mathrm{NH}_{3}$ can hydrogen bond to water.
(b) What is the solubility of ammonia in water in moles per liter?

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Key Concepts

Hydrogen Bonding

Hydrogen bonding is a type of strong dipole-dipole interaction that occurs when a hydrogen atom covalently bonded to an electronegative atom (such as oxygen, nitrogen, or fluorine) interacts with a lone pair of electrons on another electronegative atom. In the context of ammonia and water, the hydrogen atoms in ammonia, though bound to nitrogen, can engage in hydrogen bonding with the oxygen atoms in water which have lone pairs, while the lone pair on the nitrogen in ammonia may also accept hydrogen bonds from water molecules. This mutual interaction enhances the solubility of ammonia in water.

Molarity Conversion

Converting solubility from grams per liter to moles per liter involves the concept of molar mass, which is the mass of one mole of a substance. By dividing the mass concentration (in grams per liter) by the molar mass (in grams per mole) of ammonia, one can determine its concentration in moles per liter. This conversion is fundamental in chemistry for relating the mass of substances to the amount of particles present in a solution.

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