00:01
So this problem gives us the equation 2 nh4n03, ammonium nitrate, solid, decomposes into 2n2 gas plus o2 gas plus 4h2 gas.
00:24
And we want to find the volume of the complete decomposition of 1 .55 kilograms of ammonium nitrate.
00:36
Nh4n03.
00:38
And so first we can find the number of moles of ammonium nitrate.
00:42
First there's one kilogram in a thousand grams and then divided by the molar mass of ammonium nitrate 80 .043 grams per mole.
00:55
And that gives us our number of moles of ammonium nitrate to be 19 .3646 moles of nh3.
01:07
And so now that we have the moles of ammonium nitrate, we can find the moles of each of these three gases, nitrogen, oxygen, and water.
01:17
And so to do this, we take our 19 .3646 moles of nh4, n .03.
01:28
And first we'll find moles of n2.
01:31
So there's two moles of nh4 n03 in two moles.
01:41
Of n2 and so we get that same value for the number of moles of n2 19 .3646 moles of n2 now we do the same thing with the other two gases are 19 .3646 46 moles of ammonium nitrate now we want to do oxygen so we have two moles of ammonium nitrate and one mole of o two which gives us 9 .6823 moles of o2.
02:26
Now we do the same thing for water, our 19 .3646 moles of ammonium nitrate.
02:40
We do a mold -to -mole ratio again...