00:01
Okay, so we know the current density, which is j here, can be equal to current divided by area.
00:05
So therefore, current i should be equal to ja.
00:07
So the current density in this case is given as 1 .5 times 10 to 5 times 10 to 5 to 5 x x .5, ampere meter per meter.
00:12
And the area should be equal to pi times the diameter divided by 2 to the power 2 to the power of 92 meter.
00:19
If you can't 1 meter, it's equal to 1 .02 times 10 to the power of negative 3 meter.
00:24
So eventually you have area is equal to 2 .601 pi, times 10 to the power of negative 7 meter square.
00:30
So now it's plugging back to the equation to determine the currents, which is equal to 1 .50 times 10 to the power of 6 ampere per meter square, multiplied by 2 .601 pi times 10 to the power of negative 7 meter square.
00:50
And this will give us the current is equal to 1 .23 ampere.
00:58
So now let's determine the drift velocity.
01:00
So when the current can be equal to nqvda, n is the electron density, which is equal to 1.
01:06
I'm sorry, 8 .5 times 10 to the power of 28 per meter cube in this question.
01:12
And when the current is equal to 1 .23 ampere...