Question
An 18-gauge copper wire (diameter 1.02 mm) carries a current with a current density of $3.20 \times 10{^6} A/m{^2}$. The density of free electrons for copper is $8.5 \times 10^{28}$ electrons per cubic meter. Calculate (a) the current in the wire and (b) the drift velocity of electrons in the wire.
Step 1
20 \times 10^{6} A/m^{2}$ and the diameter of the wire $d = 1.02 mm$. We can calculate the current $I$ in the wire using the formula $I = J \times A$, where $A$ is the cross-sectional area of the wire. Show more…
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An 18 gauge copper wire (diameter $1.02 \mathrm{~mm}$ ) carries a current with a current density of $3.20 \times 10^{6} \mathrm{~A} / \mathrm{m}^{2} .$ The density of free electrons for copper is $8.5 \times 10^{28}$ electrons per cubic meter. Calculate (a) the current in the wire and (b) the magnitude of the drift velocity of electrons in the wire.
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