Question
An 18 gauge copper wire (diameter $1.02 \mathrm{~mm}$ ) carries a current with a current density of $3.20 \times 10^{6} \mathrm{~A} / \mathrm{m}^{2} .$ The density of free electrons for copper is $8.5 \times 10^{28}$ electrons per cubic meter. Calculate (a) the current in the wire and (b) the magnitude of the drift velocity of electrons in the wire.
Step 1
The diameter of the wire is given as $1.02 \mathrm{~mm}$, so the radius will be half of the diameter. Therefore, the radius $r$ is given by: \[ r = \frac{d}{2} = \frac{1.02}{2} = 0.51 \mathrm{~mm} = 0.51 \times 10^{-3} \mathrm{~m} \] Show more…
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An 18-gauge copper wire (diameter 1.02 mm) carries a current with a current density of $3.20 \times 10{^6} A/m{^2}$. The density of free electrons for copper is $8.5 \times 10^{28}$ electrons per cubic meter. Calculate (a) the current in the wire and (b) the drift velocity of electrons in the wire.
Current, Resistance, and Electromotive Force
Current
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