00:01
I will now give my explanation to part a.
00:05
Recore that the probability distribution of the number of successes obtained is called binomial probability distribution.
00:14
Here's the binomial distribution formula, where n is the number of trials.
00:19
For our problem, six reservations are made, so n equals 6.
00:27
X is the number of successes desired.
00:30
In our case, will be the number of people with reservations.
00:33
That show up.
00:36
P is the probability of getting a success in one trial.
00:42
20 % of those making reservations do not appear for the trip, so the probability that they do appear is 1 minus 0 .2 equals 0 .8.
00:57
And finally, q is the probability of getting a failure in one trial.
01:03
Which is 0 .2.
01:07
A problem states that an airport limousine can accommodate up to four passengers on any one trip.
01:15
So let us visualize this.
01:18
The limousine has four seats and can accommodate four people.
01:38
If at least one person show up, then he or she cannot be accommodated and we will have at least 5 people in total.
01:54
So, having at least one person with a reservation that cannot be accommodated means at least 5 passengers will show up and that probability will be p of x larger or equal to 5 which equals p of x equal 5 plus p of x equals 6.
02:23
We just plug in the number into our binomial distribution formula and we'll get this the following.
03:18
And this is our final answer.
03:32
Let us move to part b.
03:36
Here's the formula for the expected value of random variable y.
03:42
For our problem, y is the number of empty seats and and p y equals y is the probability that a trip has y empty seats.
03:54
Now let us construct the following table.
04:03
Where the first column is y, the second column is the number of pupil that show up...