00:01
So the net torque can be equal to the perpendicular distance times the force, which is equal to rf sine theta.
00:08
Invention, we have negative 2a sine theta times qe.
00:11
Okay? and the torque can be also equal to the moment of inertia times the second derivative of charge over time.
00:19
And this will give us negative omega square, which is angular speed square, times the angle theta, and then times the moment of inertia.
00:35
So therefore, we have negative omega square theta times moment of inertia is equal to negative 2a, sine theta, times qe.
00:59
Okay? it's because the electric force on each charge is along the horizontal direction.
01:08
So therefore, the perpendicular distance that is relative to the electric force must be the vertical direction, which is the perpendicular distance, okay, which is 2a sine theta.
01:21
And then we know that sine theta can be approximately equal to theta, since the angle theta is really small in this case, okay? so therefore, we can substitute back into the equation, then we have negative omega -square -theta times i is equal to negative 2a -theta times q.
01:50
Then as you can tell, negative sign can be cancelled out and theta, theta can be cancelled out.
01:57
Therefore we have omega square times i is equal to 2aqe.
02:10
Then we know angular velocity can be equal to 2 pi times frequency.
02:19
Therefore we'll have 2 pi times f square is equal to 2qae over moment of inertia...