00:01
So according to problem 15, there's an electric dipole, meaning a configuration of same and opposite charges, same and opposite charges.
00:13
Inside a uniform electric field, a vector.
00:18
It says horizontal meaning it points.
00:21
Let's take it that it points, yeah.
00:23
To the right.
00:24
Okay, the separation is between the two charges is two times a.
00:32
And it says that the electric dipole is displaced.
00:37
Maybe a better expression is that it is rotated, rotated about its center of mass, by an external factor or force anyway.
00:49
And at some point, this external factor disappears.
00:58
And naturally, the dipole tends to go back to its equilibrium position.
01:06
Okay.
01:07
Okay, so we have a restoring force as we will see in a minute.
01:11
And the exercise has two tasks.
01:15
It asks for the case that the two charges of the dipole have exactly the same mass to calculate the frequency of oscillation and that in that this is the frequency of oscillation.
01:34
And the that the two charges have a different mass with each other that the frequency of oscillation changes to this expression here.
01:45
Okay, let's continue immediately.
01:48
So, this kind of exercises basically is exactly what we do.
01:56
This kind of exercises follow exactly what we do in the case that we need to calculate the frequency of oscillation for harmonic oscillations.
02:06
Let's do it, let's first draw the forces accepted on the two charges.
02:14
So that's an electric point in to the right.
02:17
Therefore, for the positive charge, there's an lp force which points again to the right.
02:24
But for the negative recharge particle, then naturally there's an electric force pointing to the left.
02:30
Okay, but the magnitude of all the two forces is exactly the same.
02:37
And let's use e for the magnitude of the electric field.
02:41
Okay, and the magnitude of the force is just two times e.
02:45
Okay, now, let's, let's, let's, let's say, is the force accepted on the two charges that forces, forces that we charge us to stay to stay as a part of the dipole.
03:07
Okay.
03:09
Now if we decompose t, this constant force there, into two components, one component that is parallel to the electric field, another one that is perpendicular to the electric field.
03:22
Again, the simple indicates parallel, this symbol indicates perpendicular.
03:27
Okay, we can say it is quite easy to see exactly as we usually do in exercises with harmonic oscillator that the parallel component is cancelled by the electric force therefore the magnitude of our t parallel which equals a simple trichonometry this is t times cosine theta equals q e in the electric force and now the other component t perpendicular which is the restoring forces the force that pushes the charge uh yeah except on the on the charges support the charges and this is the force that forces the the dipole to go back to its equilibrium position okay that's why we call it restoring force and again simple trigonometry if this is theta the magnet of t perpendicular is just t times sine theta and if we place t from here from this equation meaning t equals qe divided by cost theta which is divided divided by cost theta times sine theta this expression is simply the definition of tangent theta.
05:05
And now, if we take theta small, it's been given by the guidelines.
05:13
Okay.
05:14
Then we end up with an expression for the magnitude of the restoring force as q times a times, times theta.
05:20
Okay.
05:22
Now, now that we have the magnitude of the restoring force, we can work out to find out the frequency of oscillation.
05:32
Okay.
05:35
Again, it's the same...