00:01
Okay, to do this problem, first we have to find the maximum efficiency, and our maximum efficiency is going to be the carnot cycle, and that's going to be th minus tc divided by th, right? it's just a difference of the temperatures of the hot and cold reservoirs divided by the temperature of the hot reservoir.
00:16
But importantly, this formula has to be used with kelvin.
00:20
So let's convert our temperatures to kelvin.
00:23
We just add 273, so we'll get 293 kelvin, and we'll get 278 kelvin.
00:31
Kelvin.
00:32
At then, so let's plug these numbers in.
00:34
293 kelvin minus 278 kelvin divided by 293 kelvin to get us our efficiency of about 0 .0512 or like 5 .12%.
00:49
Okay? this is the maximum possible efficiency.
00:53
Never is going to happen to reality, but there it is.
00:56
And so that's the first answer.
01:00
Next, we have to figure out the qh, the amount of energy that's going to be taken in from the warm reservoir.
01:08
And the time is going to be one hour, okay? it's because we know the power...