00:01
In this problem, we are told that we have these two half reactions taking place within an electrochemical cell, and we want to determine what the overall cell potential is at 25 degrees celsius.
00:11
We are at non -standard conditions for the compartment of the cell that contains the copper metal, and so we first need to calculate what the cell potential is, and then relate that to the cell potential at standard conditions for the standard hydrogen, road half reaction in order to determine the overall cell potential.
00:35
So we are given a value for the solubility equilibrium constant ksp for cu -o -h -2.
00:42
So we can begin by writing out the solubility reaction of that corresponds to.
00:47
So we have c -u -o -h -2 as a solid, and it reversibly dissociates into c -u -2 -plus aqueous ions, and 2 oh minus aqueous ions.
01:09
And so we can write out the equilibrium expression that this corresponds to, which would be equal to the solubility equilibrium constant ksp.
01:19
Based on the aqueous species, that would just be equal to the concentration of cu2 plus times the concentration of oh minus squared.
01:31
We have values for ksp, and we are told that the concentration of naoh is 0 .10 molar, so that corresponds to the concentration of oh minus ions.
01:42
So we have everything that we need to solve for the concentration of co2 plus in the copper electrode compartment of this electrochemical cell.
01:52
So we can solve that by rearranging this equation to say that the concentration of co2 plus is equal to ksp divided by the concentration of oh2, minus squared.
02:11
And now we just plug in what we are given in the problem.
02:14
We were told that ksp is equal to 1 .6 times 10 to the negative 19.
02:22
And we divide this by that 0 .10 molar concentration of n -a -o -h, and we square it.
02:33
And so the concentration of cu to plus ions in aqueous solution comes out to 1 .6.
02:43
Times 10 to the negative 17th molar in that copper electrode portion of the electrochemical cell...