00:01
Hello friends in this problem it is given an electron in cathode radio accelerated from initial velocity 2 into 10 to the power 4 meter per second to final velocity 6 into 10 to the power 6 meter per second in the distance of 1 .5 cm or 0 .015 meter how long does the electron take to travel 1 .5 centimeter.
00:45
So we have to calculate the time to travel the distance and we have to calculate the acceleration.
00:53
Let us start solving it.
01:00
This is your final position minus initial position.
01:04
So it can be written as first part.
01:08
Change in position final minus initial is called to half of initial velocity plus final velocity divided by two.
01:17
Sorry, already two i have written into time.
01:22
So time you may calculate from here 2 into final position minus initial position divided by initial velocity plus final velocity.
01:35
So 2 it is given 0 .015 meter upon 2 into 10 to the power 4 plus 6 into 10 to over 6.
01:46
So time you will get 4 .9 10 to the power 9...