00:01
In this exercise, we have an electron that is confined to a one -dimensional box, and we have the information that the ground state energy of the electron is equal to 0 .01 electron volt.
00:14
In question a, we have to find what is the length of the box.
00:22
So what i'm going to do is to write the ground state energy as h squared divided by 8ml squared, this is the formula for the ground state energy.
00:36
And if we want to find l, i'm going to isolate l here.
00:40
So l squared is equal to h squared divided by 8me1.
00:47
And for that reason, l is equal to h divided by the square root of 8me1.
00:59
So l is equal to 6 .63 times 10 to the minus 2 .3.
01:05
24 joules second divided by the square root of 8 times the mass of the electron, which is 9 .1 times 10 to the minus 31, times the ground state energy, which is 0 .01 electron volts.
01:23
And i'm going to multiply this by 1 .6 times 10 to the minus 19 joules per electron volt, just to convert the energy unit.
01:35
So l is equal to 6 .14 times 10 to the minus 9 meters, which is the same as 6 .14 nanometers.
01:53
In question b, we have to sketch the wave functions of the three states that have the lowest energies.
02:01
These states are the ground state and equals 1.
02:05
The first excited state and equals 2.
02:09
And the second excited state n equals 3.
02:14
And we know i'm going to do first for n equals 1.
02:18
So here i have l.
02:20
Here i have 0, which is the first wall of the box.
02:28
We know that for all of these cases, the wave function vanishes at the walls.
02:37
And for the ground state, there are no nodes of the wave function.
02:42
Function in between the walls and the wave function looks like a sign.
02:50
And for each subsequent excited state, there is one additional node in the wave function.
02:58
So this here is for n equals 1, the ground state.
03:05
Now i'm going to sketch for n equals 2, that is the first excited state, where there should be one node.
03:19
So it's one node and then the wave function vanishes.
03:24
This is the wave function for n equals 2.
03:28
And for n equals 3, there are two nodes.
03:37
So basically the way function starts at 0, then there are 1, 2, and 3 nodes.
03:49
And then, i'm sorry, there are 2 nodes, of course, not 3.
03:54
Because n equals 2 is the, n equals 3 is the second excited state.
03:59
So there's one and two nodes, and this is a sketch of the wave function for n equals 3.
04:15
Now for question c, we have to find what is the wavelength of the electron for the second excited state.
04:30
Notice that the wavelength can be read from the graph that we have just drawn.
04:39
So notice that one wavelength is the distance between two consecutive nodes of the wave function.
04:50
So this here is the wavelength.
04:58
And in total for the second excited state, we have the distance.
05:05
Sorry, this is the wavelength, not l.
05:07
This is the wavelength.
05:10
And for the second excited state here, we have n equals 3.
05:21
We have that the distance l is equal to three halves of the wavelength...