00:01
In this exercise, we have an electron that's bound to an atom, and this electron has an orbital quantum number l equals 2.
00:10
And in question a, we have to find what is the magnitude of the angular momentum of the electron.
00:16
And we know that the magnitude of the angular momentum, capital l squared, is equal to the orbital quantum number l times l plus 1 times hbar squared.
00:28
So in our case, l squared is equal to 2 times 3 times h bar squared.
00:35
So this is 6h bar squared.
00:39
And for the reason, the magnitude of the angular momentum is the square root of 6 times h ball.
00:49
In question b, we have to find what are the possible values of the z component of the angular momentum, lz.
00:59
And remember that the possible values of any of the components of the angular momentum range from minus lh bar to lh bar.
01:22
So in this case, the possible values of lz are minus 2h bar, minus h bar, minus h bar, 0, h bar, and 2h bar.
01:38
So the range is from minus lh bar to lh bar with steps of 1h bar.
01:45
So this here is the answer to question b.
01:53
And in question c, we have to sketch the possible orientations of the angular momentum vector.
02:04
So this here, i'm going to take this to be the x -axis.
02:10
Okay, and the angular momentum i'm going to draw in blue, but before i do that, in the x -axis we have, actually, this is the l -z -axis, and here we have the zero angular momentum.
02:31
Here we have the h -bar, and here we have the 2 -h -bar, down here, the minus h -bar, and down here minus 2 -h -bar.
02:46
So we know that the magnitude of the vector l is the square root of 6 times h bar.
02:56
That's a constant...