00:02
In this question, we have an electron.
00:06
It's moving at a speed of 7 .2 times 10 .6 meters per second.
00:15
And then it's in a magnetic field, uniform magnetic field of 83 mili tesla.
00:24
So we want to calculate the maximum and minimum force acting on the electron due to the field and calculate the angle between the electrons velocity and magnetic field if the acceleration is of a certain value.
00:38
And so to do part a, k, we'll be using the magnetic force equals to qb, sine theta, this is the magnitude.
00:53
So the maximum force, k is when sine data is 1, so it's just qbb.
01:02
So you just substitute 1 .6 times 10 to the power negative 19, times 7 .2 times the power 6, 83 times the power negative 3.
01:15
And the maximum force is 9 .56 times 10 to the power negative 14 movements.
01:22
Okay, so this is the answer for part a.
01:26
Then for part b, find a minimum force.
01:30
From the formula fb equals to qbb side data f minimum it occurs when data is equal to zero degrees so f minimum is equal to zero okay so this is the answer for part b and then for part c we are given the acceleration is 4 .90 times 10 to the power of 14 meters per second square.
02:29
So we want to find an angle between b and b...