Question
An electron is moving in a straight line with a velocity of $4.0 \times 10^{5} \mathrm{m} / \mathrm{s}$. It enters a region $5.0 \mathrm{cm}$ long where it undergoes an acceleration of $6.0 \times 10^{12} \mathrm{m} / \mathrm{s}^{2}$ along the same straight line. (a) What is the electron's velocity when it emerges from this region? b) How long does the electron take to cross the region?
Step 1
We can use the second equation of motion for this, which is given by: \[v^2 = u^2 + 2ad\] where: - \(v\) is the final velocity, - \(u\) is the initial velocity, - \(a\) is the acceleration, and - \(d\) is the distance. Show more…
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