Question
An incandescent lightbulb radiates at a rate of $60.0 \mathrm{W}$ when the temperature of its filament is $2820 \mathrm{K}$. During a brownout (temporary drop in line voltage), the power radiated drops to 58.0 W. What is the temperature of the filament? Ignore changes in the filament's length and cross-sectional area due to the temperature change.
Step 1
Mathematically, it can be written as $P = \sigma A T^4$, where $P$ is the power radiated, $\sigma$ is the Stefan-Boltzmann constant, $A$ is the surface area, and $T$ is the absolute temperature. Show more…
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An incandescent light bulb radiates at a rate of $60.0 \mathrm{W}$ when the temperature of its filament is $2820 \mathrm{K}$. During a brownout (temporary drop in line voltage), the power radiated drops to $58.0 \mathrm{W} .$ What is the temperature of the filament? Neglect changes in the filament's length and cross-sectional area due to the temperature change. (tutorial: light bulb)
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