00:01
For this question we have an x -ray coming in with wave length of 0 .09 nanometers and it's scattered off in the backward direction from a free electron it gets scattered off in the exact opposite direction to its initial motion so it's a 180 degrees scattering, compton scattering and the electron moves off with some momentum you want to calculate what is this magnitude of momentum of the scattered photon.
00:46
So the momentum of the scattered photon will be, let me just call this p prime, h over lambda prime.
00:54
But first we have to find what is lambda prime.
00:56
So lambda prime is equals to lambda plus h over mc times 1 minus cosine phi.
01:06
This 5 is the angle of scattering which is 180 degrees.
01:12
So what we get is 2h over mc.
01:30
So now i'm putting the constants, right? the planks constant, the mass of the electron, and the speed of light.
01:40
Then we should be able to calculate the width length to be about 0 .09485 nanometers.
01:51
And after which we can put it into the brogly's formula.
02:09
You can get the momentum of the photon, right, the scattered photon...