99 \times 10^9 \mathrm{N \cdot m^2/C^2}$), $Q$ is the charge on the sphere, and $r$ is the distance from the center of the sphere.
We are given that $E = 4.90 \times 10^4 \mathrm{N/C}$ and $r = 21.0 \mathrm{cm} = 0.21 \mathrm{m}$. Plugging these values into the
Show more…