00:01
All right, we've got a situation here where we've got one lens that's converging here.
00:06
Converging has a focal length of 12 centimeters.
00:12
And then 16 centimeters over here, we have our object, v -o -1, it's 16 centimeters away.
00:20
And then over here, 20 centimeters away, we have a diverging lens, near lens, right? 20 centimeters over here.
00:29
And so we're going to try to figure out where does the object end up? and what size is it, and et cetera, et cetera.
00:36
All right, so the deal is that we're going to start off by taking this object right here, and we're going to find out where its image is using the focal equation.
00:46
So 1 over 12, because of this converging lens, equals 1 over 16 plus 1 over d .i.
00:56
So that means our image, we're going to convert this into 48s, 4 over 48 equals 3 over 48.
01:04
Plus 1 for 48.
01:07
So that means our di equals 48 centimeters.
01:12
And then also, we can look at this by making a ray tracing, make our center ray come through here.
01:20
And way over here, we're going to get a pretty good -sized inverted image up here.
01:25
And di over do minus di over do.
01:29
It's going to give us our magnification.
01:31
It's going to be a minus 4.
01:32
That's why it's inverted.
01:34
It's negative.
01:35
And it's large.
01:37
All right, so now we have, i'm going to scroll down, and we're going to start looking at when we have this for our object, for our second lens.
01:49
All right, so here is our diverging lens right here...