00:01
For this problem on the topic of rotation, we are shown an object that is made of two disk -shaped sections, a and b, and it is rotating about an axis to the center of disk a.
00:11
The masses and radii of disks a and b are 2kg and 0 .2 kg, and 25 centimeters and 2 .5 centimeters respectively.
00:20
We want to find the moment of inertia for the object, and we want to find the time it will take for the object to come to a stop if it is rotating with an initial angular velocity, of minus 2 pi radiance per second due to a friction, frictional torque of 0 .2 newton meters.
00:40
Now, each object has its own moment of inertia, ia and ib, and disk a has a mass capital m2kg and radius capital r 25 centimeters.
00:50
It rotates about its center of mass, while disk b with a mass little m, 0 .2kg, and radius little r, 2 .5 centimeters, rotates a distance, of d, which is big r minus little r away from the axis.
01:08
This means that the parallel axis theorem must be used to determine the overall moment of inertia for disk b, which is ib prime.
01:16
The total moment of inertia is the sum of the two.
01:19
The torque is 0 .2 newton meters and is applied and will cause an angular acceleration alpha.
01:26
If the disc initially rotates at minus 2 pi radiance per second, then we can use kind of to determine how long it will take to slow down...