Question
An object must have a speed of at least $11.2 \mathrm{~km} / \mathrm{s}$ to escape from the Earth's gravitational field. At what temperature will $v_{\mathrm{rms}}$ for $\mathrm{H}_{2}$ molecules equal the escape speed? Repeat for $\mathrm{N}_{2}$ molecules. $\left(M_{\mathrm{H} 2}=2.0 \mathrm{~kg} / \mathrm{kmol}\right.$ and $M_{\mathrm{N} 2}=28 \mathrm{~kg} / \mathrm{kmol}$.)
Step 1
Step 1: We know that the root mean square speed $v_{rms}$ of a gas molecule is given by the formula: \[v_{rms} = \sqrt{\frac{3kT}{m}}\] where $k$ is the Boltzmann constant, $T$ is the temperature, and $m$ is the mass of the molecule. Show more…
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An object must have a speed of at least $11.2 \mathrm{~km} / \mathrm{s}$ to escape from the Earth's gravitational field. At what temperature will $u_{\mathrm{rms}}$ for $\mathrm{H}_{2}$ molecules equal the escape speed? Repeat for $\mathrm{N}_{2}$ molecules. $\left(M_{\mathrm{H} 2}=2.0 \mathrm{~kg} / \mathrm{kmol}\right.$ and $\left.M_{\mathrm{N} 2}=28 \mathrm{~kg} / \mathrm{kmol} .\right)$
The escape velocity of any object from Earth is $11.2 \mathrm{km} / \mathrm{s}$. (a) Express this speed in $\mathrm{m} / \mathrm{s}$ and $\mathrm{km} / \mathrm{h}$. (b) At what temperature would oxygen molecules (molecular mass is equal to $32.0 \mathrm{g} / \mathrm{mol}$ ) have an average velocity $v_{\mathrm{rms}}$ equal to Earth's escape velocity of $11.1 \mathrm{km} / \mathrm{s} ?$
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