Question
The escape velocity of any object from Earth is $11.2 \mathrm{km} / \mathrm{s}$.(a) Express this speed in $\mathrm{m} / \mathrm{s}$ and $\mathrm{km} / \mathrm{h}$. (b) At what temperature would oxygen molecules (molecular mass is equal to $32.0 \mathrm{g} / \mathrm{mol}$ ) have an average velocity $v_{\mathrm{rms}}$ equal toEarth's escape velocity of $11.1 \mathrm{km} / \mathrm{s} ?$
Step 1
We know that 1 kilometer is equal to 1000 meters. Therefore, the escape velocity in meters per second is $v = 11.2 \times 10^{3} \, \mathrm{m/s}$. Show more…
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The escape velocity of any object from Earth is 11.2 km/s. (a) Express this speed in m/s and km/h. (b) At what temperature would oxygen molecules (molecular mass is equal to 32.0 g/mol) have an average velocity vrms equal to Earth’s escape velocity of 11.1 km/s?
The escape velocity of any object from Earth is 11.1 $\mathrm{km} / \mathrm{s} .$ At what temperature would oxygen molecules (molar mass is equal to $32.0 \mathrm{g} / \mathrm{mol}$ ) have root-mean-square velocity $v_{\mathrm{rms}}$ equal to Earth's escape velocity of $11.1 \mathrm{km} /$ s?
An object must have a speed of at least $11.2 \mathrm{~km} / \mathrm{s}$ to escape from the Earth's gravitational field. At what temperature will $v_{\mathrm{rms}}$ for $\mathrm{H}_{2}$ molecules equal the escape speed? Repeat for $\mathrm{N}_{2}$ molecules. $\left(M_{\mathrm{H} 2}=2.0 \mathrm{~kg} / \mathrm{kmol}\right.$ and $M_{\mathrm{N} 2}=28 \mathrm{~kg} / \mathrm{kmol}$.)
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