Question
An object of height 3 $\mathrm{cm}$ is placed at $25 \mathrm{cm}$ in front of a converging lens of focal length $20 \mathrm{cm} .$ Behind the lens there is a concave mirror of focal length $20 \mathrm{cm} .$ The distance between the lens and the mirror is $5 \mathrm{cm}$. Find the location, orientation and size of the final image.
Step 1
We can use the lens formula, which is given by: \[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \] where \(f\) is the focal length of the lens, \(v\) is the image distance, and \(u\) is the object distance. Show more…
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An object of height 3 cm is placed at a distance of 25 $\mathrm{cm}$ in front of a converging lens of focal length $20 \mathrm{cm},$ to be referred to as the first lens. Behind the lens there is another converging lens of focal length $20 \mathrm{cm}$ placed $10 \mathrm{cm}$ from the first lens. There is a concave mirror of focal length 15 $\mathrm{cm}$ placed $50 \mathrm{cm}$ from the second lens. Find the location, orientation, and size of the final image.
An object of height 2 $\mathrm{cm}$ is placed at $50 \mathrm{cm}$ in front of a diverging lens of focal length $40 \mathrm{cm} .$ Behind the lens, there is a convex mirror of focal length $15 \mathrm{cm}$ placed 30 cm from the converging lens. Find the location, orientation, and size of the final image.
An object of height $3.0 \mathrm{cm}$ is placed at $25 \mathrm{cm}$ in front of a diverging lens of focal length $20 \mathrm{cm}$. Behind the diverging lens, there is a converging lens of focal length $20 \mathrm{cm} .$ The distance between the lenses is $5.0 \mathrm{cm}$. Find the location and size of the final image.
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