Question
An open vessel containing water is given a constant acceleration $a$ in the horizontal direction. Then the free surface of water gets sloped with the horizontal at an angle $\theta$ given by(A) $\theta=\tan ^{-1}\left(\frac{a}{g}\right)$(B) $\theta=\tan ^{-1}\left(\frac{g}{a}\right)$(C) $\theta=\sin ^{-1}\left(\frac{a}{g}\right)$(D) $\theta=\cos ^{-1}\left(\frac{g}{a}\right)$
Step 1
Due to this acceleration, a pseudo force acts on the liquid in the vessel in the opposite direction of the acceleration. As a result, the free surface of the water gets sloped with the horizontal at an angle $\theta$. Show more…
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Solids and Fluids
Section B
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