Question
$\Lambda$ rectangular container of base dimensions $2 \mathrm{~m} \times 1 \mathrm{~m}$ and height $0.5 \mathrm{~m}$ is filled with water upto height of $0.2 \mathrm{~m}$. 'The mass of the empty container is $1 \mathrm{~kg}$. The coefficient of friction between conLainer and plane is $0.5$. The container is placed on the pane inclined at $45^{\circ}$ to the horizontal. The angle of the water surface to the horizontal is(a) $\tan ^{\prime}\left(\frac{1}{2}\right)$(b) $\tan ^{1} 2$(c) $\tan ^{\prime}\left(\frac{1}{3}\right)$(d) $\tan ^{1} 3$
Step 1
The acceleration is given by the equation $a = g \sin 45^{\circ} - \mu g \cos 45^{\circ}$, where $g$ is the acceleration due to gravity, $\mu$ is the coefficient of friction, and $45^{\circ}$ is the angle of inclination. Show more…
Show all steps
Your feedback will help us improve your experience
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A rectangular container, of base dimensions $0.4 \mathrm{m} \times$ $0.2 \mathrm{m}$ and height $0.4 \mathrm{m},$ is filled with water to a depth of $0.2 \mathrm{m} ;$ the mass of the empty container is $10 \mathrm{kg} .$ The container is placed on a plane inclined at $30^{\circ}$ to the horizontal. If the coefficient of sliding friction between the container and the plane is $0.3,$ determine the angle of the water surface relative to the horizontal.
A container, partially filled with a liquid, slides down a plane inclined at an angle ̑ to the horizontal. The coefficient of friction ̐ < tan ̑. Find the angle that the surface of the liquid in the container forms with the inclined plane.
An open vessel containing water is given a constant acceleration $a$ in the horizontal direction. Then the free surface of water gets sloped with the horizontal at an angle $\theta$ given by (A) $\theta=\tan ^{-1}\left(\frac{a}{g}\right)$ (B) $\theta=\tan ^{-1}\left(\frac{g}{a}\right)$ (C) $\theta=\sin ^{-1}\left(\frac{a}{g}\right)$ (D) $\theta=\cos ^{-1}\left(\frac{g}{a}\right)$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD