Question
An oscillator is producing FM waves of frequency 2 $\mathrm{KHz}$ with a variation of $10 \mathrm{kHz}$. What is the modulating index(a) $0.20$(b) $5.0$(c) $0.67$(d) $1.5$
Step 1
Step 1: The frequency modulation index is given by the formula: \[ \beta = \frac{\Delta f}{f_m} \] where \(\Delta f\) is the maximum frequency deviation and \(f_m\) is the modulating frequency. Show more…
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The modulation index of a FM signal is $0.25$. If modulating frequency is $2 \mathrm{kHz}$, the maximum deviation in frequency would be (a) $500 \mathrm{~Hz}$ (b) $1000 \mathrm{~Hz}$ (c) $1500 \mathrm{~Hz}$ (d) $500 \mathrm{kHz}$
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Round 2
The modulation index of an FM carrier having a carrier swing of 200 kHz and a modulating signal 10 kHz is (a) 5 (b) 10 (c) 20 (d) 25
The modulation index of an FM carrier having a carrier swing of $200 \mathrm{kHz}$ and a modulating signal $10 \mathrm{kHz}$ is (a) 10 (b) 30 (c) 20 (d) 40
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